Consider the reactions :
`2S_(2)O_(3)^(2-)(aq)+l_(2)(s)toS_(4)O_(6)^(2-)(aq)+2l^(-)(aq)`
`S_(2)O_(3)^(2-)(aq)+2Br_(2)(l)+5H_(2)O(l)to2SO_(4)^(2-)(aq)+4Br^(-)(aq)+10H^(+)(aq)`
Why does the same reductant, thiosulphate react differently with iodine and bromine?

Explanation

To understand why thiosulphate reacts differently with iodine and bromine, we need to analyze the reactions and the oxidation states involved.

### Step-by-Step Solution:

1. **Identify the Reactions**:
- The first reaction is:
\[
2 \text{S}_2\text{O}_3^{2-} (aq) + \text{I}_2 (s) \rightarrow \text{S}_4\text{O}_6^{2-} (aq) + 2 \text{I}^- (aq)
...