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A red blood cell placed in 50% NaCl solu...

A red blood cell placed in 50% NaCl solution will :

A

undergo crenation

B

swell and eventually burst due to water intake

C

stay the same size

D

none of the above

Text Solution

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The correct Answer is:
To solve the question regarding what happens to a red blood cell (RBC) when placed in a 50% NaCl solution, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Environment**: - A 50% NaCl solution is a highly concentrated saline solution. In biological terms, this is considered a hypertonic solution compared to the internal environment of the red blood cell. 2. **Osmosis Concept**: - Osmosis is the movement of water across a semipermeable membrane from an area of lower solute concentration to an area of higher solute concentration. 3. **Effect on Red Blood Cell**: - When an RBC is placed in a hypertonic solution (like 50% NaCl), water inside the RBC will move out into the surrounding solution to balance the solute concentrations. 4. **Resulting Changes in the RBC**: - As water leaves the RBC, it will begin to shrink or crenate. This process is known as crenation, where the cell loses water and shrivels up. 5. **Conclusion**: - Therefore, the correct answer to the question is that the red blood cell will undergo crenation when placed in a 50% NaCl solution. ### Final Answer: A red blood cell placed in a 50% NaCl solution will undergo crenation. ---

To solve the question regarding what happens to a red blood cell (RBC) when placed in a 50% NaCl solution, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Environment**: - A 50% NaCl solution is a highly concentrated saline solution. In biological terms, this is considered a hypertonic solution compared to the internal environment of the red blood cell. 2. **Osmosis Concept**: ...
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