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A car moves at a uniform speed of 431/5 ...

A car moves at a uniform speed of 43`1/5` km hour how much distance will it cover in 3`1/3` hours

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To solve the problem of how much distance a car will cover at a speed of \(43 \frac{1}{5}\) km/h for \(3 \frac{1}{3}\) hours, we will follow these steps: ### Step 1: Convert the mixed numbers to improper fractions. - For \(43 \frac{1}{5}\): \[ 43 \frac{1}{5} = 43 + \frac{1}{5} = \frac{43 \times 5 + 1}{5} = \frac{215 + 1}{5} = \frac{216}{5} \] - For \(3 \frac{1}{3}\): \[ 3 \frac{1}{3} = 3 + \frac{1}{3} = \frac{3 \times 3 + 1}{3} = \frac{9 + 1}{3} = \frac{10}{3} \] ### Step 2: Use the formula for distance. The formula for distance is: \[ \text{Distance} = \text{Speed} \times \text{Time} \] Substituting the values we found: \[ \text{Distance} = \frac{216}{5} \times \frac{10}{3} \] ### Step 3: Multiply the fractions. To multiply the fractions, we multiply the numerators and the denominators: \[ \text{Distance} = \frac{216 \times 10}{5 \times 3} = \frac{2160}{15} \] ### Step 4: Simplify the fraction. Now, we simplify \(\frac{2160}{15}\): - Dividing both the numerator and the denominator by 15: \[ \frac{2160 \div 15}{15 \div 15} = \frac{144}{1} = 144 \] ### Final Answer: The distance covered by the car is **144 km**. ---
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