Home
Class 7
MATHS
Simplify : 8.349 - 2.57 + 6.28 - 9.6...

Simplify : 8.349 - 2.57 + 6.28 - 9.6

Text Solution

AI Generated Solution

The correct Answer is:
To simplify the expression \( 8.349 - 2.57 + 6.28 - 9.6 \), we can follow these steps: ### Step 1: Rearrange the expression We can rearrange the expression to group the addition and subtraction: \[ 8.349 + 6.28 - 2.57 - 9.6 \] ### Step 2: Add the first two numbers Now, we will add \( 8.349 \) and \( 6.28 \). To do this, we can align the decimal points: ``` 8.349 + 6.280 -------- ``` Now, we add column by column: - In the thousandths place: \( 9 + 0 = 9 \) - In the hundredths place: \( 4 + 8 = 12 \) (write down 2 and carry over 1) - In the tenths place: \( 3 + 2 + 1 = 6 \) - In the units place: \( 8 + 6 = 14 \) So, we have: \[ 8.349 + 6.28 = 14.629 \] ### Step 3: Add the last two numbers Next, we will add \( 2.57 \) and \( 9.6 \): ``` 2.570 + 9.600 -------- ``` Now, we add column by column: - In the thousandths place: \( 0 + 0 = 0 \) - In the hundredths place: \( 7 + 0 = 7 \) - In the tenths place: \( 5 + 6 = 11 \) (write down 1 and carry over 1) - In the units place: \( 2 + 9 + 1 = 12 \) So, we have: \[ 2.57 + 9.6 = 12.17 \] ### Step 4: Subtract the two results Now, we need to subtract \( 12.17 \) from \( 14.629 \): ``` 14.629 - 12.170 -------- ``` Now, we subtract column by column: - In the thousandths place: \( 9 - 0 = 9 \) - In the hundredths place: \( 2 - 7 \) (we need to borrow, so it becomes \( 12 - 7 = 5 \)) - In the tenths place: \( 5 - 1 = 4 \) - In the units place: \( 4 - 2 = 2 \) So, we have: \[ 14.629 - 12.17 = 2.459 \] ### Final Answer Thus, the simplified result is: \[ \boxed{2.459} \]
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

Simplify: 8 1/4-\ 2 5/6

Simplify: 36.54 - 15.79 + 85.2 - 57.615

Simplify : (8) 1/4 - (2) 5/6

Simplify : i^(-6)

Simplify: 6\ x\ 112

Simplify: 8/9+(-11)/6

Simplify : [8-(1.08+6.9)]^(2)

simplify: 6 1/6-\ 5 1/5\

Simplify: 4 5/6-2 3/8+3 7/(12)

Simplify : a^(6)-b^(6)