Find the products :
`0.423 xx15`

Answer

To find the product of \(0.423\) and \(15\), we can follow these steps:

### Step 1: Multiply without the decimal
First, we will ignore the decimal point and multiply \(423\) by \(15\).

\[ 423 \times 15 \]

### Step 2: Perform the multiplication
We can break it down as follows:

1. Multiply \(15\) by \(3\):
\[ 15 \times 3 = 45 \quad (\text{write } 5 \text{ and carry } 4) \]

2. Multiply \(15\) by \(2\) (from \(423\)):
\[ 15 \times 2 = 30 \quad (\text{add the carry } 4) \Rightarrow 30 + 4 = 34 \quad (\text{write } 4 \text{ and carry } 3) \]

3. Multiply \(15\) by \(4\) (from \(423\)):
\[ 15 \times 4 = 60 \quad (\text{add the carry } 3) \Rightarrow 60 + 3 = 63 \]

Now, putting it all together, we have:

\[ 423 \times 15 = 6345 \]

### Step 3: Place the decimal point
Now we need to consider the decimal point. The number \(0.423\) has \(3\) digits after the decimal point. Therefore, we need to place the decimal point in our result \(6345\) such that there are \(3\) digits after it.

So we move the decimal point \(3\) places to the left:

\[ 6345 \rightarrow 6.345 \]

### Final Answer
Thus, the product of \(0.423\) and \(15\) is:

\[ \boxed{6.345} \]

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