Find the product :
`2.35 xx7.2`

Answer

To find the product of the decimal numbers \(2.35\) and \(7.2\), we can follow these steps:

### Step 1: Ignore the Decimals
First, we will ignore the decimal points and multiply the numbers as if they were whole numbers. So, we will multiply \(235\) (from \(2.35\)) by \(72\) (from \(7.2\)).

### Step 2: Multiply the Whole Numbers
Now, we will multiply \(235\) by \(72\).

1. Multiply \(235\) by \(2\):
- \(2 \times 5 = 10\) (write \(0\), carry \(1\))
- \(2 \times 3 = 6\), plus \(1\) (carry) = \(7\)
- \(2 \times 2 = 4\)
- So, \(235 \times 2 = 470\)

2. Multiply \(235\) by \(7\):
- \(7 \times 5 = 35\) (write \(5\), carry \(3\))
- \(7 \times 3 = 21\), plus \(3\) (carry) = \(24\) (write \(4\), carry \(2\))
- \(7 \times 2 = 14\), plus \(2\) (carry) = \(16\)
- So, \(235 \times 7 = 1645\)

### Step 3: Add the Results
Now, we will add the two results together:
- \(470\) (from \(235 \times 2\))
- \(1645\) (from \(235 \times 7\))

Aligning the numbers for addition:
```
1645
+ 470
-------
```
Adding:
- \(5 + 0 = 5\)
- \(4 + 7 = 11\) (write \(1\), carry \(1\))
- \(6 + 4 = 10\), plus \(1\) (carry) = \(11\) (write \(1\), carry \(1\))
- \(1 + 1 = 2\)

So, \(470 + 1645 = 2115\).

### Step 4: Count the Decimal Places
Now we need to place the decimal point in the product. The original numbers \(2.35\) has \(2\) decimal places, and \(7.2\) has \(1\) decimal place. Therefore, the total number of decimal places is \(2 + 1 = 3\).

### Step 5: Place the Decimal Point
We take the result \(2115\) and place the decimal point \(3\) places from the right:
- \(2115\) becomes \(21.15\).

### Final Answer
Thus, the product of \(2.35\) and \(7.2\) is \(16.92\).

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