Find the product :
`0.37 xx0.26`

Answer

To find the product of the decimals \(0.37\) and \(0.26\), we will follow these steps:

### Step 1: Ignore the decimal points and multiply as whole numbers
First, we will multiply \(37\) by \(26\) (ignoring the decimal points for now).

### Step 2: Multiply \(37\) by \(26\)
- Multiply \(37\) by \(6\) (the units digit of \(26\)):
- \(6 \times 7 = 42\) (write down \(2\) and carry over \(4\))
- \(6 \times 3 = 18\), plus the carry \(4\) gives \(22\) (write down \(22\))

So, the result of \(37 \times 6 = 222\).

- Now multiply \(37\) by \(2\) (the tens digit of \(26\)):
- \(2 \times 7 = 14\) (write down \(4\) and carry over \(1\))
- \(2 \times 3 = 6\), plus the carry \(1\) gives \(7\) (write down \(7\))

So, the result of \(37 \times 20 = 740\).

### Step 3: Add the two results together
Now, we add the two results:
```
222
+ 740
------
962
```

### Step 4: Count the decimal places
Now, we need to place the decimal point in the product.
- The original numbers \(0.37\) and \(0.26\) each have 2 decimal places.
- Therefore, we have a total of \(2 + 2 = 4\) decimal places.

### Step 5: Place the decimal point
We place the decimal point in \(962\) to get \(0.0962\).

### Final Answer
Thus, the product of \(0.37\) and \(0.26\) is:
\[ \boxed{0.0962} \]

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