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Solve the equations and check your answer in the case:
`x-(2x-(3x-4)/(7))= (4x-27)/(3)-3`

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To solve the equation \( x - \left(2x - \frac{(3x - 4)}{7}\right) = \frac{(4x - 27)}{3} - 3 \), we will follow these steps: ### Step 1: Simplify the left side of the equation We start with the left side: \[ x - \left(2x - \frac{(3x - 4)}{7}\right) \] Distributing the negative sign: \[ x - 2x + \frac{(3x - 4)}{7} \] This simplifies to: \[ -x + \frac{(3x - 4)}{7} \] ### Step 2: Combine terms on the left side To combine the terms, we need a common denominator. The common denominator is 7: \[ -x = -\frac{7x}{7} \] Thus, we rewrite the left side: \[ -\frac{7x}{7} + \frac{(3x - 4)}{7} = \frac{-7x + 3x - 4}{7} = \frac{-4x - 4}{7} \] ### Step 3: Simplify the right side of the equation Now we simplify the right side: \[ \frac{(4x - 27)}{3} - 3 \] Convert 3 to a fraction with a denominator of 3: \[ 3 = \frac{9}{3} \] So, we have: \[ \frac{(4x - 27)}{3} - \frac{9}{3} = \frac{(4x - 27 - 9)}{3} = \frac{(4x - 36)}{3} \] ### Step 4: Set the two sides equal Now we have: \[ \frac{-4x - 4}{7} = \frac{(4x - 36)}{3} \] ### Step 5: Cross-multiply to eliminate the fractions Cross-multiplying gives us: \[ -4x - 4) \cdot 3 = (4x - 36) \cdot 7 \] This simplifies to: \[ -12x - 12 = 28x - 252 \] ### Step 6: Rearrange the equation Now, we will move all terms involving \(x\) to one side and constant terms to the other side: \[ -12x - 28x = -252 + 12 \] This simplifies to: \[ -40x = -240 \] ### Step 7: Solve for \(x\) Dividing both sides by -40: \[ x = \frac{-240}{-40} = 6 \] ### Step 8: Check the solution Substituting \(x = 6\) back into the original equation: Left side: \[ 6 - \left(2(6) - \frac{(3(6) - 4)}{7}\right) = 6 - \left(12 - \frac{18 - 4}{7}\right) = 6 - \left(12 - \frac{14}{7}\right) = 6 - \left(12 - 2\right) = 6 - 10 = -4 \] Right side: \[ \frac{(4(6) - 27)}{3} - 3 = \frac{(24 - 27)}{3} - 3 = \frac{-3}{3} - 3 = -1 - 3 = -4 \] Both sides are equal, confirming our solution is correct. ### Final Answer: \[ x = 6 \]
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