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Convert it 47^(@)20' into radian....

Convert it `47^(@)20`' into radian.

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To convert \( 47^\circ 20' \) into radians, follow these steps: ### Step 1: Convert minutes to degrees 1. We know that \( 1 \text{ degree} = 60 \text{ minutes} \). 2. Therefore, \( 20' \) (minutes) can be converted to degrees by dividing by 60: \[ 20' = \frac{20}{60} = \frac{1}{3} \text{ degrees} \] ### Step 2: Add the degrees 3. Now, add the degrees from Step 1 to the whole degrees: \[ 47^\circ + \frac{1}{3}^\circ = 47 + \frac{1}{3} = \frac{141}{3} \text{ degrees} \] ### Step 3: Convert degrees to radians 4. We use the conversion factor \( \frac{\pi \text{ radians}}{180 \text{ degrees}} \) to convert degrees to radians: \[ \text{Radians} = \frac{141}{3} \times \frac{\pi}{180} \] ### Step 4: Simplify the expression 5. Simplifying the expression: \[ \text{Radians} = \frac{141\pi}{3 \times 180} = \frac{141\pi}{540} \] ### Step 5: Further simplify 6. We can simplify \( \frac{141}{540} \): \[ \frac{141}{540} \approx 0.26167 \text{ (approximately)} \] Thus, \[ \text{Radians} \approx 0.26167\pi \] ### Final Result The final result of converting \( 47^\circ 20' \) into radians is approximately: \[ 0.26167\pi \text{ radians} \] ---
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ADVANCED MATHS BY ABHINAY MATHS ENGLISH-GEOMETRY TRIANGLES-QUESTIONS
  1. If (2x+17)^(@),(x+4)^(@) are complementary, find x :

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  2. If (5y+62)^(@), (22^(@)+y) are supplementary, find y :

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  3. Convert it 47^(@)20' into radian.

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  4. Convert it 63^(@) 14'51" into radian .

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  5. In the figure AB||CD, angle ABE=100^(@). Find angleCDE:

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  6. In the following figure, if PQ || RS, angle MXQ=135^(@) and angle MYR=...

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  7. In a figure , AB is a straight line , Find (x+y):

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  8. In a figure AB|\|DE, angle ABC=67^(@) and angle EDC=23^(@) . Find angl...

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  9. In a figure AB|\| CD, find x^(@):

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  10. In the given fig. AB|\|CD. Find the value of x.

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  11. In the figure , AB|\|CD and PQ, QR intersect AB and CD both at E, F G ...

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  12. In a Delta ABC, angle A+ angle B =145^(@), angle C+2angleB =180^(@) fi...

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  13. In the following fig. AD=BD=AC and angle CAF=81^(@), then find angle A...

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  14. In a Delta ABD, AB=BC=CD & AD=BD. Find angle ADB.

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  15. In a triangle ABC, angle B=angleC=78^(@). D & E are two points on side...

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  16. In triangle ABC, angleA is equal to 120^@ . There is a point D inside...

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  17. In a triangle DEF, points A, B, and C are C are taken on DE, DF and EF...

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  18. I is the incentre of Delta ABC, angle ABC=60^(@) and angle ACB=50^(@)....

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  19. In a Delta ABC, CD is the angle bisector of interior angle C. Which me...

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  20. In a DeltaABC, angleA=60^@ , AB = 3 cm , AC = 4 cm .Find the length o...

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