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If in a triangle ABC, BE and CF are two medians perpendicular to each other and if `AB=19` cm and `AC=22 cm` then the length of BC is

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To find the length of side BC in triangle ABC, where BE and CF are medians that are perpendicular to each other, and given that AB = 19 cm and AC = 22 cm, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Values**: - AB = 19 cm - AC = 22 cm 2. **Use the Property of Medians**: - When two medians of a triangle are perpendicular to each other, the following relationship holds: \[ AB^2 + AC^2 = 5 \times BC^2 \] 3. **Substitute the Known Values**: - Substitute the values of AB and AC into the equation: \[ 19^2 + 22^2 = 5 \times BC^2 \] 4. **Calculate the Squares**: - Calculate \(19^2\) and \(22^2\): \[ 19^2 = 361 \] \[ 22^2 = 484 \] 5. **Add the Squares**: - Add the results: \[ 361 + 484 = 845 \] 6. **Set Up the Equation**: - Now we have: \[ 845 = 5 \times BC^2 \] 7. **Solve for \(BC^2\)**: - Divide both sides by 5: \[ BC^2 = \frac{845}{5} = 169 \] 8. **Find the Length of BC**: - Take the square root of both sides to find BC: \[ BC = \sqrt{169} = 13 \text{ cm} \] ### Final Answer: The length of side BC is **13 cm**.
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