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In Delta ABC, G is the centroid , AB=15c...

In `Delta ABC, G` is the centroid , AB=15cm, BC=18 cm, and AC=25 cm . Find GD , Where D is the mid point of BC:

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To solve the problem step by step, we will follow the process outlined in the video transcript. ### Step 1: Understand the Problem We have a triangle ABC with sides AB = 15 cm, BC = 18 cm, and AC = 25 cm. We need to find the length of GD, where G is the centroid of the triangle and D is the midpoint of side BC. ### Step 2: Find the Length of AD (Median) To find GD, we first need to calculate the length of the median AD. We can use Apollonius's theorem, which states: \[ AB^2 + AC^2 = 2AD^2 + \left(\frac{BC}{2}\right)^2 \] Substituting the given values: - \(AB = 15\) cm - \(AC = 25\) cm - \(BC = 18\) cm Calculating: \[ 15^2 + 25^2 = 2AD^2 + \left(\frac{18}{2}\right)^2 \] Calculating the squares: \[ 225 + 625 = 2AD^2 + 9^2 \] \[ 225 + 625 = 2AD^2 + 81 \] \[ 850 = 2AD^2 + 81 \] ### Step 3: Solve for AD^2 Now, isolate \(AD^2\): \[ 850 - 81 = 2AD^2 \] \[ 769 = 2AD^2 \] \[ AD^2 = \frac{769}{2} \] ### Step 4: Calculate AD Now, take the square root to find AD: \[ AD = \sqrt{\frac{769}{2}} = \frac{\sqrt{769}}{\sqrt{2}} = \frac{\sqrt{769 \cdot 2}}{2} = \frac{\sqrt{1538}}{2} \] ### Step 5: Find GD The centroid G divides the median AD in the ratio 2:1. Therefore, we can express GD as: \[ GD = \frac{1}{3}AD \] Substituting the value of AD: \[ GD = \frac{1}{3} \cdot \frac{\sqrt{1538}}{2} \] \[ GD = \frac{\sqrt{1538}}{6} \] ### Final Answer Thus, the length of GD is: \[ GD = \frac{\sqrt{1538}}{6} \text{ cm} \]
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