`int1/(x(logx-1)(logx+1))\ dx`

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Find the value of int dx/(x(logx -1)(logx + 1))

Evaluate: int1/(xlogxlog(logx))dx

Evaluate : int(1)/(xlogxlog(logx))dx

int(1)/(xlogx(2+logx))dx=

int(logx-1)/(x)dx

int(1)/(x(logx))dx=?

Evaluate int[1/logx-1/(logx)^2]dx

Evaluate: int(logx)/((1+logx)^2)\ dx

int7^(x logx)(1+logx)dx=

int(logx)/(x(1+logx)(2+logx))dx=