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A bag contains Rs. 180. In which Rs. 1, ...

A bag contains Rs. 180. In which Rs. 1, 50p, 25p coins. Their ratio are 2 : 3:4. Then find number of all types of coins separately.

A

`40,60,80`

B

`160,120,180`

C

`80,120,160`

D

`80,120,150`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Understand the ratio of coins The ratio of the coins is given as Rs. 1 : 50p : 25p = 2 : 3 : 4. This means: - Let the number of Rs. 1 coins be \( 2k \) - Let the number of 50p coins be \( 3k \) - Let the number of 25p coins be \( 4k \) ### Step 2: Calculate the total value of each type of coin Next, we need to calculate the total value contributed by each type of coin: - The value of Rs. 1 coins = \( 2k \times 1 = 2k \) rupees - The value of 50p coins = \( 3k \times 0.5 = \frac{3k}{2} \) rupees - The value of 25p coins = \( 4k \times 0.25 = k \) rupees ### Step 3: Set up the equation for the total amount The total amount in the bag is Rs. 180. Therefore, we can write the equation: \[ 2k + \frac{3k}{2} + k = 180 \] ### Step 4: Combine like terms To combine the terms, we need a common denominator. The common denominator for the terms is 2: \[ 2k + \frac{3k}{2} + k = 180 \] Converting \( k \) to have a denominator of 2: \[ 2k + \frac{3k}{2} + \frac{2k}{2} = 180 \] This simplifies to: \[ \frac{4k + 3k + 2k}{2} = 180 \] \[ \frac{9k}{2} = 180 \] ### Step 5: Solve for \( k \) Now, we can solve for \( k \): \[ 9k = 180 \times 2 \] \[ 9k = 360 \] \[ k = \frac{360}{9} = 40 \] ### Step 6: Find the number of each type of coin Now that we have \( k \), we can find the number of each type of coin: - Number of Rs. 1 coins = \( 2k = 2 \times 40 = 80 \) - Number of 50p coins = \( 3k = 3 \times 40 = 120 \) - Number of 25p coins = \( 4k = 4 \times 40 = 160 \) ### Final Answer Thus, the number of each type of coin is: - Rs. 1 coins: 80 - 50p coins: 120 - 25p coins: 160 ---
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