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Find the HCF of the polynomials f(x)= 6(...

Find the HCF of the polynomials `f(x)= 6(x^(3) +3x^(2)) (x^(2)-16) (x^(2) + 9x + 18) and g(x) = 8(x^(4) + 4x^(3)) (x^(2) + 6x + 9)^(2)`

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To find the HCF (Highest Common Factor) of the given polynomials \( f(x) \) and \( g(x) \), we will follow these steps: ### Step 1: Factor the first polynomial \( f(x) \) Given: \[ f(x) = 6(x^3 + 3x^2)(x^2 - 16)(x^2 + 9x + 18) \] 1. **Factor out the coefficients and common terms:** - \( 6 = 2 \cdot 3 \) - From \( x^3 + 3x^2 \), we can factor out \( x^2 \): \[ x^3 + 3x^2 = x^2(x + 3) \] - \( x^2 - 16 \) can be factored as a difference of squares: \[ x^2 - 16 = (x - 4)(x + 4) \] - For \( x^2 + 9x + 18 \), we can factor it as: \[ x^2 + 9x + 18 = (x + 3)(x + 6) \] 2. **Combine all factors:** \[ f(x) = 6 \cdot x^2 \cdot (x + 3) \cdot (x - 4) \cdot (x + 4) \cdot (x + 3)(x + 6) \] \[ = 6x^2(x + 3)^2(x - 4)(x + 4)(x + 6) \] ### Step 2: Factor the second polynomial \( g(x) \) Given: \[ g(x) = 8(x^4 + 4x^3)(x^2 + 6x + 9)^2 \] 1. **Factor out the coefficients and common terms:** - \( 8 = 2^3 \) - From \( x^4 + 4x^3 \), we can factor out \( x^3 \): \[ x^4 + 4x^3 = x^3(x + 4) \] - For \( (x^2 + 6x + 9)^2 \), we can recognize it as a perfect square: \[ x^2 + 6x + 9 = (x + 3)^2 \] - Therefore: \[ (x^2 + 6x + 9)^2 = ((x + 3)^2)^2 = (x + 3)^4 \] 2. **Combine all factors:** \[ g(x) = 8 \cdot x^3 \cdot (x + 4) \cdot (x + 3)^4 \] \[ = 2^3 \cdot x^3 \cdot (x + 4) \cdot (x + 3)^4 \] ### Step 3: Find the HCF of \( f(x) \) and \( g(x) \) Now we have: - \( f(x) = 6x^2(x + 3)^2(x - 4)(x + 4)(x + 6) \) - \( g(x) = 2^3 x^3 (x + 4)(x + 3)^4 \) 1. **Identify the common factors:** - Coefficient: \( 6 = 2 \cdot 3 \) and \( 8 = 2^3 \) → HCF of coefficients is \( 2^1 = 2 \) - \( x^2 \) from \( f(x) \) and \( x^3 \) from \( g(x) \) → HCF is \( x^2 \) - \( (x + 3)^2 \) from \( f(x) \) and \( (x + 3)^4 \) from \( g(x) \) → HCF is \( (x + 3)^2 \) - \( (x + 4) \) is common in both. - \( (x - 4) \) and \( (x + 6) \) are not common in \( g(x) \). 2. **Combine the common factors:** \[ \text{HCF} = 2 \cdot x^2 \cdot (x + 3)^2 \cdot (x + 4) \] ### Final Answer: \[ \text{HCF} = 2x^2(x + 3)^2(x + 4) \] ---
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ADVANCED MATHS BY ABHINAY MATHS ENGLISH-ALGEBRA THEORY-Example
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