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If (x^(2)-1)/(x)=sqrt5 and x is positi...

If `(x^(2)-1)/(x)=sqrt5` and x is positive number find `(x^(2) + (1)/(x^(2))) (x+ (1)/(x))=` ?

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To solve the problem step by step, we start with the equation given: \[ \frac{x^2 - 1}{x} = \sqrt{5} \] ### Step 1: Rewrite the equation We can rewrite the equation as follows: \[ x - \frac{1}{x} = \sqrt{5} \] **Hint:** Rearranging the equation can help simplify the problem. ### Step 2: Square both sides Next, we square both sides of the equation: \[ \left(x - \frac{1}{x}\right)^2 = (\sqrt{5})^2 \] This gives us: \[ x^2 - 2\cdot x \cdot \frac{1}{x} + \frac{1}{x^2} = 5 \] **Hint:** Remember that \((a - b)^2 = a^2 - 2ab + b^2\). ### Step 3: Simplify the equation Now, simplify the equation: \[ x^2 - 2 + \frac{1}{x^2} = 5 \] Adding 2 to both sides results in: \[ x^2 + \frac{1}{x^2} = 7 \] **Hint:** Isolate the term you want to find by moving other terms to the other side. ### Step 4: Find \(x + \frac{1}{x}\) Now, we need to find \(x + \frac{1}{x}\). We can use the identity: \[ \left(x + \frac{1}{x}\right)^2 = x^2 + 2 + \frac{1}{x^2} \] From the previous step, we know: \[ x^2 + \frac{1}{x^2} = 7 \] So we can substitute: \[ \left(x + \frac{1}{x}\right)^2 = 7 + 2 = 9 \] Taking the square root of both sides gives: \[ x + \frac{1}{x} = 3 \] **Hint:** Use the square root to find the positive solution since \(x\) is positive. ### Step 5: Calculate the final expression Now we need to find: \[ \left(x^2 + \frac{1}{x^2}\right) \left(x + \frac{1}{x}\right) \] Substituting the values we found: \[ 7 \cdot 3 = 21 \] ### Final Answer Thus, the final answer is: \[ \boxed{21} \] ---
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ADVANCED MATHS BY ABHINAY MATHS ENGLISH-ALGEBRA THEORY-Example
  1. If x+ (1)/(x)=3, then x^(5) + (1)/(x^(5))= ?

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  2. If x+ (1)/(x)=3, then x^(6) + (1)/(x^(6))=?

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  3. If (x^(2)-1)/(x)=sqrt5 and x is positive number find (x^(2) + (1)/(x...

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  4. If x^(4) + (1)/(x^(4)) = 322 find x^(3)- (1)/(x^(3))= ?

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  5. If (x-a) (x-b)=1 " & " a-b + 5= 0 find (x-a)^(3) - (1)/((x-a)^(3))= ?

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  6. If (x-1)^(2) + (y-2)^(2)= 0 then x+y= ?

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  7. If (a-2)^(2) + (b-3)^(2) + (c-11)^(2)=0 find sqrt(a+b+c)=?

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  8. If a^(2) + b^(2) +c^(2)=2 (a-b +c)-3 then find a-b + c= ?

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  9. If a^(2) + b^(2) + c^(2) = 2(a +2b -2c)-9 then find a+b+c=?

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  10. If 5x^(2) + 4xy + y^(2) + 2x + 1= 0 then find the value of x, y

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  11. If x^(2) + y^(2) + z^(2) + 12x + 4y + 5=0 find x^(12) + y+ z^(30)= ?

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  12. If (x+ y-z -1)^(2) + (z+ x-y - 2)^(2) + (z+y-x-4)^(2)=0 find x+ y+z=?

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  13. If a= 297, b= 298, c= 299 and find a^(2) + b^(2) + c^(2) - ab - bc - c...

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  14. If a^(2) + b^(2) + c^(2) =ab + bc + ca find (a + c)/(b)= ?

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  15. If a^(2) +b^(2) +c^(2) = ab + bc + ca then (a+b)/(c ) + (b+c)/(a) + ...

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  16. If a^(2) +b^(2) +c^(2) = ab + bc + ca then (c )/(a+b) + (b)/(a +c)+...

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  17. If a^(2) +b^(2) +c^(2) = ab + bc + ca then ((a+b)/(c ) + (b+c)/(a) ...

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  18. If a+b+c= 0, then (a+b)/(c )= ?

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  19. If a+b+c= 0, then (a+b)/(c ) + (b+c)/(a) + (c +a)/(b)= ?

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  20. If a+b+c= 0, then (c )/(a+b) + (b)/(a+c) + (a)/(b + c)= ?

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