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In right angle Delta ABC, BD divides D...

In right angle `Delta ABC`, BD divides `Delta ABC ` into two equal perimeter `Delta `. Find AD if AC = 10 cm , BC = 8 cm ` angle B = 90^(@)`

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To solve the problem step by step, we will follow these instructions: ### Step 1: Understand the Triangle We are given a right triangle \( \Delta ABC \) where: - \( AC = 10 \, \text{cm} \) - \( BC = 8 \, \text{cm} \) - \( \angle B = 90^\circ \) ### Step 2: Find the Length of Side \( AB \) Using the Pythagorean theorem: \[ AB^2 + BC^2 = AC^2 \] Substituting the known values: \[ AB^2 + 8^2 = 10^2 \] \[ AB^2 + 64 = 100 \] \[ AB^2 = 100 - 64 = 36 \] Taking the square root: \[ AB = \sqrt{36} = 6 \, \text{cm} \] ### Step 3: Set Up the Perimeter Equation Let \( AD = x \) and \( DB = y \). Since \( BD \) divides \( \Delta ABC \) into two triangles with equal perimeters, we can write the perimeter of both triangles: - Perimeter of \( \Delta ABD = AB + AD + BD = 6 + x + y \) - Perimeter of \( \Delta CBD = BC + CD + BD = 8 + (10 - x) + y \) ### Step 4: Set the Perimeters Equal Set the two perimeters equal: \[ 6 + x + y = 8 + (10 - x) + y \] Simplifying this equation: \[ 6 + x + y = 18 - x + y \] Subtracting \( y \) from both sides: \[ 6 + x = 18 - x \] Adding \( x \) to both sides: \[ 6 + 2x = 18 \] Subtracting 6 from both sides: \[ 2x = 12 \] Dividing by 2: \[ x = 6 \, \text{cm} \] ### Step 5: Conclusion Since \( AD = x \), we find that: \[ AD = 6 \, \text{cm} \] Thus, the final answer is: \[ \text{AD} = 6 \, \text{cm} \] ---
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