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In the figure, O is centre of a circle. ...

In the figure, O is centre of a circle. If `angle BAC = 20^(@) and angle ACB = 30^(@)`. Find `angle AOC`

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The correct Answer is:
`angle AOC = 100^(@)`
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In the given figure, O is the centre of the circle. If angle BAO = 30^@ and angle BCO = 50^@ , then angle AOC is equal to: दिए गए आकृति में, O वृत्त का केंद्र है। यदि angle BAO = 30^@ और angle BCO = 50^@ , तो angle AOC का मान है :

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