`tanA/2tanB/2+tanB/2tanC/2+tanC/2tanA/2=1`

If A+B+C= pi/2 , show that : tanA tanB + tanB tanC + tanC tanA=1

12. lf in triangle ABC ,cos theta (sinB + sinC) = sinA, then (A) cot^2theta/2=tanB/2tanC/2 (B) tan^2 theta/2=tanB/2+tanC/2 (C) tan^2 theta/2=tanB/2tanC/2D) costhetacos(B-C)/2-cos(B+C)/2=0

In a DeltaABC , if tanA/2=5/6 and tanB/2=20/37 then tanC/2=

In any triangle ABC , (tanA/2-tanB/2)/(tanA/2+tanB/2) is equal to

tanA +tanB + tanC = tanA tanB tanC if

In DeltaABC , prove that: (b-c)/(a)=(tanB/2-tanC/2)/(tanB/2+tanC/2)

If A + B + C = π , Prove that tanB tanC+tanC tanA+tanA tanB=1+secA . sec B . secC.

In DeltaABC , prove that: a/(b+c)=(1-tanB/2tanC/2)/(1+tanB/2tanC/2)