A small ball moving with a velocity 10m/s,horizontally (as shown in figure) strikes a rough horizontal surface having `mu=0.5` .If the coefficient of restitution is e=0.4.Horizontal component of velocity of ball after Ist impact will be?(g=10m/`s^(2)`)

A block of mass m=5kg is resting on a rough horizontal surface for which the coefficient of friction is 0.2 . When a force F=40N is applied, the acceleration of the block will be (g=10m//s^(2)) .

A ball moving with speed v collides with a horizontal smooth surface at an angle theta with normal to surface as shown in figure. If coefficient of restitution of collision is e, then find v'

A ball is dropped from a heght of 3.6 m and strikes a horizontal surface . It rebounds from the horizontal surface to height h . Calculate h , if coefficient of restitution is 0.6

If a ball is thrown vertically upwards with a velocity of 40m//s , then velocity of the ball after 2s will be (g = 10m//s^(2))

A block of mass 10kg is placed on a rough horizontal surface having coefficient of friction mu=0.5 . If a horizontal force of 100N is acting on it, then acceleration of the will be.

A 250 g ball moving horizontally with velocity 10.0m/s strikes inclined surface of a 720g smooth wedge as shown in the figure. The wedge is placed at rest on a frictionless horizontal ground. If the coefficient of restitution is 0.8, calculate the velocity of the wedge after the impact.

A ball after freely falling from a height of 4.9m strikes a horizontal plane. If the coefficient of restitution is 3/4 , the ball will strike second time with the plane after

A ball falls from a height of 10m on to a horizontal plane. If the coefficient of restitution is 0.4 , then the velocity with which it rebounds from the plane after second collision is