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The radius of the circle passing through...

The radius of the circle passing through the foci of `(x^(2))/(16) + (y^(2))/(9) =1`, and having centre (0, 3) is

A

4

B

3

C

`sqrt(12)`

D

`(7)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`a^(2) = 16 , b^(2) = 9`
` implies e^(2) =1-(b^(2))/(a^(2)) = 1 - (9)/(16) = (7)/(16) implies e= (sqrt(7))/(4)`
`"foci" ( pm ae, 0) = (pm sqrt(7), 0)`
Centre (0,3) `:. r = sqrt(7+9) = sqrt(16) =4 `
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