`int_(-1)^(1)(x-[2x])dx=`

Let [x] denote the greatest integer less than or equal to x, then the value of the integral int_(-1)^(1)(|x|-2[x])dx is equal to

int_(-1)^(1)(x^(2)+x+3)dx

int_(-1)^(1)(x^(2)-2x+3)dx

Evalaute int_(-1)^(1)(x^2-3x+2)dx

Evaluate int_(-1)^(1)(x^2-3x+2)dx

The value of the integral int_(1)^(3)|(x-1)(x-2)|dx is

int_(-1)^(1)[x^(2)-x+1]dx, where [.] denotes thegreatest integer function,is equal to

int_(-1)^(1)(x^(2)+x)/(x^(2)+1)dx=

" (iii) "1=int_(0)^(1)(x-1)(x+2)dx