Two particles of equal mass m are moving with velocities `vhati` and `v((hati+hatj)/(2))` respectively. If the particles collide completely inelastically, then the energy lost in the process is

Two particles of mass m & 2m have velocities u hat( j) & u hat( i ) respectively . They collide completely inelastically. Find the loss in kinetic energy of the system.

Two particles of mass 2m and m moving with speed v and 2v respectively perpendicular to each other collides perfectly inelastically, then Loss in kinetic energy of the system

Two particles of mass 2m and m moving with speed v and 2v respectively pependicular to each other collides perfectly inelastically, then Speed of the particles after collision

Two particles of mass 2m and m moving with speed v and 2v respectively pependicular to each other collides perfectly inelastically, then Find the angle with the horizontal to which the particles move after collision.

Two particles of same mass 'm' moving with velocities vecv_1= vhati, and vecv_2 = (v/2)hati + (v/2)hatj collide in-elastically. Find the loss in kinetic energy

Two particles of same mass m moving with velocities u_(1) and u_(2) collide perfectly inelastically. The loss of energy would be :

Three particles with masses 10, 20 and 40gm are moving with velocities 10hati, 10hatj and 10hatk m/sec respectively. If due to some interaction the first particle comes to rest and the velocity of second becomes ) (3hati+4hatj) m/sec. then the velocity of third particle after the interaction is-

Two particles of equal mass have velocities 2hati ms^(-1) " and " 2hatj ms^(-1) . First particle has an acceleration (hati+hatj) ms^(-2) while the acceleration of the second particle is zero. The centre of mass of the two particles moves in ?

Two particles of masses m and 2 m has initial velocity vecu_(1)=2hati+3hatj(m)/(s) and vecu_(2)=-4hati+3hatj(m)/(s) Respectivley. These particles have constant acceleration veca_(1)=4hati+3hatj((m)/(s^(2))) and veca_(2)=-4hati-2hatj((m)/(s^(2))) Respectively. Path of the centre of the centre of mass of this two particle system will be:

Two particles are moving with velocities v_(1)=hati+thatj+hatk and v_(2)=thati+thatj+2hatk m//s respectively. Time at which they are moving perpendicular to each other is.____________(second)