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int[tan^(- 1)(secx+tanx)]dx...

`int[tan^(- 1)(secx+tanx)]dx`

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inttan^(-1)(secx+tanx)dx=?

What is inttan^(-1)(secx+tanx) dx equal to ?

int(1)/(secx+tanx)dx=

int(tanx)/(secx+tanx)dx=

(d)/(dx)[tan^(-1)[(secx-tanx)]=

int secx+ tan xdx

int(1)/(a secx+b tanx)dx=

Find the differentiation of y=tan^(-1)(secx+tanx)

(i) int (tanx)/((secx + tanx))dx ,(ii) int(cosecx)/((cosecx- cotx))dx

int secx tan xdx