Let `n_(1)` and `n_(2)` moles of two different ideal gases be mixed. If adiabatic coeffiecient of the two gases are `gamma_(1)` and `gamma_(2)` respectively, then adiabatic coefficient `gamma` of the mixture is given through the relation

When 1 mole of a monatomic gas is mixed with 3 moles of a diatomic gas, the value of adiabatic exponent gamma for the mixture is

x^(3)+5x^(2)+px+q=0 and x^(3)+7x^(2)+px+r=0 have two roots in common.If their third roots are gamma_(1) and gamma_(2) respectively,then | gamma_(1)+gamma_(2)|=

x^(3)+5x^(2)+px+q=0 and x^(3)+7x^(2)+px+r=0 have two roos in common. If their third roots are gamma_(1) and gamma_(2) , respectively, then |gamma_(1)-gamma_(2)|=

Two diatomic gases are mixed in mole ratio 1:2. Find the value of adiabatic exponent for this mixture of gases.

The coefficient of apparent expansion of a liquid when determined using two different vessle A and B are gamma_(1) and gamma_(2,) respectily. If the coefficient of linerar expansion of vesel A is alpha. Find the coefficient of linear expension of the vessel B.

n_(1) and n_(2) moles of two ideal gases (mo1 wt m_(1) and m_(2)) respectively at temperature T_(1)K and T_(2)K are mixed Assuming that no loss of energy the temperature of mixture becomes .

Two ideal monoatomic and diatomic gases are mixed with one another to form an ideal gas mixture. The equation of the adiabatic process of the mixture is PV^(gamma)= constant, where gamma=(11)/(7) If n_(1) and n_(2) are the number of moles of the monoatomic and diatomic gases in the mixture respectively, find the ratio (n_(1))/(n_(2))

Calculate the value of gamma for a gaseous mixture consisting of n_(1) moles of oxygen and n_(2) moles of carbon of carbon dioxide. The values of gamma for oxygen and carbon dioxide are gamma_(1) and gamma_(2) respectively. Assume the gases to be ideal. [Hint: U_(m) = U_(1) + U_(2) and U = (nRT)/(gamma-1) ]