The amplitude (A) of damped oscillator becomes half in 5 minutes. The amplitude after next 10 minutes will be

The amplitude of a damped oscillator becomes half in one minutes. The amplitude after 3 minutes will be 1/x times of the original . Determine the value of x.

The amplitude of damped oscillator becomes half in one minute. The amplitude after 3 minutes will be 1//x times the original, where x is

The amplitude of damped oscillator becomes 1/3 in 2s . Its amplitude after 6s is 1//n times the original. The value of n is

The amplitude of a damped oscillator becomes (1)/(27)^(th) of its initial value after 6 minutes. Its amplitude after 2 minutes is

The amplitude of damped oscillator decreased to 0.9 times its original magnitude is 5s . In another 10s it will decrease to alpha times its original magnitude, where alpha equals.

In damped oscillations damping froce is directly proportional to speed of ocillatior .If amplitude becomes half to its maximum value is 1 s, then after 2 s amplitude will be ( A_(0) - initial amplitude)

Amplitude of vibrations of simple pendulum is A. becomes (A)/(3) after 20 seconds. The amplitude after 60 seconds will be-

Amplitude of a damped oscillator decreases up to 0.6 times of its initial value in 5 seconds. In next 10 seconds, it decreases upto 'alpha' times of its intial value where 'alpha' is equal to ?

In a damped harmonic oscillator, periodic oscillations have ………. amplitude.