The velocity of 2 kg body is changed from `(4hat(i)+3hat(j)) ms^(-1)` to `6 ms^(-1)`. The work done on the body is

A force applied on a particle of mass 2 kg changes its velocity from (hati + 2 hatj ) ms^(-1) "to" (4hati +6hatj )ms^(-1) ​. The work done by the force in this process is :-

A particle velocity changes from (2hat(i)+3hat(j))ms^(-1) to (2hat(i)-3hat(j))ms^(-1) in 2 s. The acceleration in ms^(-2) is

A force (4hat(i)+hat(j)-2hat(k)) ms^(-1) The power exerted is

The angular velocity of a rotating body is vec omega = 4 hat i + hat j - 2 hat k . The linear velocity of the body whose position vector 2hati + 3 hat j - 3 hat k is

What force will change the velocity of a body of mass 1 kg from 20 ms^(-1) to 30 ms^(-1) in two seconds?

A particle's velocity changes from (2hat I +3 hatj) ms^(-1) in to (3 hati - 2hatj) ms^(-1) in 2s. Its average acceleration in ms^(-2) is

A body of mass 2kg is projected vertically up with velocity 5ms^(-1) . The work done on the body by gravitational force before it is brought to rest momentarily is

A force (3 hat(i)+4 hat(j)) acts on a body and displaces it by (3 hat(i)+4 hat(j))m . The work done by the force is

A force of (3 hat(i) - 1.5 hat(j)) N acts on 5 kg body. The body is at a position of (2 hat(i) - 3 hat(j)) m and is travelling at ms^(-1) . The focce acts on the body until it is at the position (hat(i) + 5 hat(j)) m . Assuming no other force does work on the body, the final speed of the body.

What force should be applied on a body of mass 500 kg to change its velocity from 4 ms^(1) to 6 ms^(-1) in one second ?