A proton (mass =`1.6times10^(-27)Kg` enters into a magnetic field of induction `3T` with a velocity of `10^(7)ms^(-1)` at `30` to the field.The force on the proton?

A proton enters a magnetic field with a velocity of 2.5 xx10^(7)ms^(-1) making an angle 30^(@) with the magnetic field. The force on the proton is (B=25T)

A proton enters a magnetic field of flux density 2*5T with a speed of 1*5xx10^7ms^-1 at an angle of 30^@ with the field, Find the force on the proton.

A proton enters a magnetic fiedl of flux density 1.5"weber"//m^(2) with a velocity of 2xx10^(-7)m//sec at an angle of 30^(@) with the field. The force on the proton will be

A proton moving withh a velocity 2.5xx10^(7)m//s enters a magnetic field of intensity 2.5T making an angle 30^(@) with the magnetic field. The force on the proton is

A beam of protons enters a uniform magnetic field of 0.3 tesla with a velocity of 4xx10^(5) m/s at an angle of 60º to the field. Then, (Mass of the proton =1.7 xx10^(-27) kg.) (1) the radius of the helical path is 1.226 xx 10^(-2) m (2) the pitch of the helix is 4.45 xx 10^(-2) m (3) the radius of the helical path is 1.226 xx 10^(-3) m (4) the pitch of the helix is 4.45xx10^(-4) m

A beam of electrons enters a uniform magnetic field of 0*3T with a velocity of 4xx10^5ms^-1 at an angle of 60^@ to the field. Find the radius of the helical path taken by the beam. Also find the pitch of the helix (distance travelled by a proton parallel to the magnetic field during one period of rotation). Mass of proton is 1*67xx10^(-27)kg .