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Revolution of the Earth is an example of...

Revolution of the Earth is an example of

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Calculate the area covered per second (m^(2)s^(-1)) by the Moon for one complete revolution round the Earth (distance of Moon from Earth =3.845 times 10^(8) and period of revolution of Moon =27""1/3 days).

What is a period of revolution of the earth satellite ? Ignore the height of satellite above the surface of the earth. Given, (i) the value of gravitational acceleration, g = 10 ms^(-2) (ii) radius of the earth, R_(g) =6400 km (take, pi = 3.14 )

In the case of peppered moth (Biston betularia) the black-coloured from became dominant over the light-coloured form in England during industrial revolution. This is an example of

In the case of peppered moth (Biston betularia) the black-coloured from became dominant over the light-coloured form in England during industrial revolution. This is an example of

In the case of peppered moth (Biston betularia) the black-coloured form became dominant over the light-coloured form in England during industrial revolution. This is an example of

In the case of peppered moth (Biston betularia) the black-coloured from became dominant over the light-coloured form in England during industrial revolution. This is an example of

Taking the rotation and revolution of the earth into account, does a tree move faster during day or during night?

Keeping the mass of the earth as constant, if its radius is reduced to 1/4th of its initial value, then the period of revolution of the earth about its own axis and passing through the centre, (in hours) is (assume the earth to be a solid sphere and its initial period of rotation as 24 h)

The period of revolution of an earth satellite close to surface of earth is 90min. The time period of aother satellite in an orbit at a distance of three times the radius of earth from its surface will be

An earth satellite makes a complete revolution around the earth in 120 minutes. If the orbit is circular calculate the height of satellite above the earth. Radius of the earth = 6400 km g = 9.8 ms^(-2) .