What is the magnitude and direction of total linears acceleration of a particle moving in a circular path of radius 0.7 m having an instantaneous angular velocity of `3.5 rad s^(-1)` and angular acceleration of `4.2 rad s^(-2)`.

Explanation

To find the magnitude and direction of the total linear acceleration of a particle moving in a circular path, we need to consider both the tangential acceleration and the centripetal (or radial) acceleration.

### Step-by-Step Solution:

1. **Identify Given Values**:
- Radius of the circular path, \( r = 0.7 \, \text{m} \)
- Instantaneous angular velocity, \( \omega = 3.5 \, \text{rad/s} \)
- Angular acceleration, \( \alpha = 4.2 \, \text{rad/s}^2 \)
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