Two particles of masses 100 gm and 300 gm have at a given time, position `2hati + 5hatj + 13hatk` and `-6hati + 4hatj -2hatk` respectively and velocities `10hati - 7hatj - 3hatk` and `-7hati - 9hatj - 6hatk` m/s respectively. Deduce the instantaneous position and velocity of the Centre of mass.

Explanation

To find the instantaneous position and velocity of the center of mass (CM) of the two particles, we can follow these steps:

### Step 1: Convert Masses to Kilograms
The masses of the particles are given in grams. We need to convert them to kilograms:
- Mass of particle 1, \( m_1 = 100 \, \text{gm} = 0.1 \, \text{kg} \)
- Mass of particle 2, \( m_2 = 300 \, \text{gm} = 0.3 \, \text{kg} \)

### Step 2: Identify the Position Vectors
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