The earth is rotating with an angular velocity of `7.3 xx 10^(-5)` rad/s. What is the tangential force needed to stop the earth in one year ? Given moment of inertia of the earth about the axis of rotation = `9.3 xx 10^(37) m^(2)`. Radius of the earth = `6.4 xx 10^(6)` m

Explanation

To find the tangential force needed to stop the Earth in one year, we can follow these steps:

### Step 1: Identify Given Values
- Angular velocity of the Earth, \( \omega_0 = 7.3 \times 10^{-5} \, \text{rad/s} \)
- Final angular velocity, \( \omega = 0 \, \text{rad/s} \) (since the Earth needs to stop)
- Moment of inertia of the Earth, \( I = 9.3 \times 10^{37} \, \text{kg m}^2 \)
- Radius of the Earth, \( R = 6.4 \times 10^{6} \, \text{m} \)
- Time to stop, \( T = 1 \, \text{year} = 365.25 \times 24 \times 60 \times 60 \, \text{s} \)
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