A body of mass 0.5 kg is whirled with a velocity of `2 ms^(-1)` using 0.5 m length string which can be withstand a tension of 15 N, Neglecting the force of gravity on the body predict whether or not the string will break.

Explanation

To determine whether the string will break while whirling a body of mass 0.5 kg at a velocity of 2 m/s using a 0.5 m long string, we need to calculate the centripetal force acting on the body and compare it with the maximum tension the string can withstand.

### Step-by-Step Solution:

**Step 1: Identify the given values.**
- Mass of the body (m) = 0.5 kg
- Velocity (v) = 2 m/s
- Length of the string (radius, r) = 0.5 m
- Maximum tension the string can withstand (T_max) = 15 N

**Step 2: Calculate the centripetal force (F_c).**
The formula for centripetal force is given by:
\[ F_c = \frac{mv^2}{r} \]

Substituting the known values:
\[ F_c = \frac{0.5 \, \text{kg} \times (2 \, \text{m/s})^2}{0.5 \, \text{m}} \]

Calculating the value:
\[ F_c = \frac{0.5 \times 4}{0.5} = \frac{2}{0.5} = 4 \, \text{N} \]

**Step 3: Compare the centripetal force with the maximum tension.**
- The calculated centripetal force (F_c) = 4 N
- The maximum tension (T_max) = 15 N

Since \( F_c < T_{max} \):
\[ 4 \, \text{N} < 15 \, \text{N} \]

**Step 4: Conclusion.**
The tension in the string (which provides the centripetal force) is less than the maximum tension the string can withstand. Therefore, the string will not break.

### Final Answer:
The string will not break.

---