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A string 1 m long can just support a wei...

A string 1 m long can just support a weight of 16 kg. Amass of 1 kg is attached to one of its ends. The body is revolved in a horizontal circle about the other fixed end of the string. Find the greatest number of revolutions made by the mass per second ? (Take g = `10 ms^(-2)`)

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To solve the problem step by step, we will start by identifying the key elements of the question and applying the relevant physics concepts. ### Step 1: Identify the forces acting on the mass The mass of 1 kg is attached to a string that can support a maximum weight of 16 kg. The maximum weight can be converted to force using the formula: \[ F = m \cdot g \] Where: - \( m = 16 \, \text{kg} \) - \( g = 10 \, \text{m/s}^2 \) Calculating the maximum force: \[ F = 16 \, \text{kg} \cdot 10 \, \text{m/s}^2 = 160 \, \text{N} \] ### Step 2: Relate centripetal force to mass and angular velocity The centripetal force (\( F_c \)) required to keep the mass moving in a circle is given by: \[ F_c = m \cdot \omega^2 \cdot r \] Where: - \( m = 1 \, \text{kg} \) (mass attached to the string) - \( r = 1 \, \text{m} \) (length of the string) - \( \omega \) is the angular velocity in radians per second. ### Step 3: Express angular velocity in terms of revolutions per second The angular velocity (\( \omega \)) can be expressed in terms of the number of revolutions per second (\( n \)): \[ \omega = 2\pi n \] ### Step 4: Substitute \( \omega \) into the centripetal force equation Substituting \( \omega \) into the centripetal force equation gives: \[ F_c = m \cdot (2\pi n)^2 \cdot r \] Substituting the known values: \[ 160 \, \text{N} = 1 \cdot (2\pi n)^2 \cdot 1 \] ### Step 5: Solve for \( n \) Now, we can simplify and solve for \( n \): \[ 160 = (2\pi n)^2 \] \[ 160 = 4\pi^2 n^2 \] \[ n^2 = \frac{160}{4\pi^2} \] \[ n^2 = \frac{40}{\pi^2} \] Taking the square root of both sides: \[ n = \sqrt{\frac{40}{\pi^2}} \] \[ n = \frac{\sqrt{40}}{\pi} \] Using \( \pi \approx 3.14 \): \[ n \approx \frac{6.32}{3.14} \approx 2.01 \] ### Step 6: Conclusion The greatest number of revolutions made by the mass per second is approximately: \[ n \approx 2 \, \text{revolutions per second} \]

To solve the problem step by step, we will start by identifying the key elements of the question and applying the relevant physics concepts. ### Step 1: Identify the forces acting on the mass The mass of 1 kg is attached to a string that can support a maximum weight of 16 kg. The maximum weight can be converted to force using the formula: \[ F = m \cdot g \] Where: - \( m = 16 \, \text{kg} \) - \( g = 10 \, \text{m/s}^2 \) ...
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ICSE-CIRCULAR MOTION -MODULE 1 (FROM CENTRIPETAL FORCE)
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