Home
Class 11
PHYSICS
"The mass of a flywheel is concentrated ...

"The mass of a flywheel is concentrated on the rim ". Why ?

Text Solution

Verified by Experts

This is to increase the moment of inertia. Hence its opposition to any change in uniform rotatory motion is large. So when-a flywheel of large M.I. is used, the engine runs smoother and steadier.
Promotional Banner

Topper's Solved these Questions

  • CIRCULAR MOTION

    ICSE|Exercise MODULE 2 (LONG ANSWER QUESTIONS)|14 Videos
  • CIRCULAR MOTION

    ICSE|Exercise MODULE 2 (SHORT ANSWER QUESTIONS)|35 Videos
  • CIRCULAR MOTION

    ICSE|Exercise MODULE 1 (FROM BANKING OR RAILS AND ROADS)|13 Videos
  • COMPETITION CARE UNIT

    ICSE|Exercise OBJECTIVE QUESTIONS FROM PREVIOUS IAS EXAMINATIONS |50 Videos

Similar Questions

Explore conceptually related problems

All the mass of an atom is concentrated in its-

Assertion:The whole mass of the atom is concentrated in the nucleus. Reason:The whole mass of the atom is concentrated in the nucleus Reason:The mass of a nucleus can be either less than or more than the sum of the masses of nucleons present in it.

A flywheel of mass 100 kg and radius 1 m is rotating at the rate of 420 rev/min. Find the constant retarding torque to stop the wheel in 14 revolutions, the mass is concentrated at the rim. M.I. of the flywheel about its axis of rotation I = mr^(2) .

the flywheel is so constructed that the entire mass of it is concentrated at its rim, because

The diameter of a flywheel is increased by 1% . Increase in its moment of interia about the central axis is

Can mass of a body be taken concentrated at its centre of mass for the purpose of calculating its rotational inertia ?

A flywheel of mass 400 kg and one metre radius makes 600 rev/minute. Assuming its mass to be concentrated at the rim, calculate the angular velocity, M.I. and energy of the flywheel.

Calculate the percentage increase in the moment of inertia about the axis of symmetry of a flywheel when the diameter of the flywheel is increased by 2%.

The figure shows the angular velocity versus time graph of a flywheel. The angle, in radians through which the flywheel turns during 25 s is

The angular position of a point over a rotating flywheel is changing according to the relation, theta = (2t^3 - 3t^2 - 4t - 5) radian. The angular acceleration of the flywheel at time, t = 1 s is