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Three point masses of 1 kg, 2kg and 3 kg...

Three point masses of 1 kg, 2kg and 3 kg lie at (0, 0), (1, 2), (3, -1), respectively. Calculate the coordinates of the centre of mass of the system.

Text Solution

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The correct Answer is:
(2,2)
`x =(m_(1)x_(1) + m_(2)x_(2) + m_(3)x_(3))//m_(1)vec(a_(1)) + m_(2)vec(a_(2)) = m_(1)veca - m_(2)veca = (m_(1) - m_(2))(m_(1)-m_(2)) vecg//m_(1) + m_(2) veca_("cm") = (m_(1)-m_(2))^(2) vecg//(m_(1) + m_(2))^(2)`
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