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A body falling vertically .downwards exp...

A body falling vertically .downwards explodes into two equal fragments when it is at a height of 200 m and has a downward velocity of ,6 just after the explosion one pf the fragments is seen to move .downward with a velocity of `8 ms^(-1)` .Calculate the position of the centre of mass of the system 5 s after ,the explosion.

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The correct Answer is:
47.5 m above the ground
The explosion is not due to any external force. So after explosion also the CM continues to move as if there was no explosion. Distance travelled after 5s is `y=y_(0) + (1//2) gt^(2) = 6 xx 5 +(1//2) 9.8 xx 25 y=152.5 m`. So C.M. is at a distance 200-152.5 = 47.5 m above the ground.
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