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If m(1) = 3 kg and m2 = 1 kg what is th...

If `m_(1) = 3` kg and `m_2 = 1` kg what is the angular momentum of the system about center of pulley ? The radius of the pulley is 0.3 m and its moment of inertia about its axle is 0.14 kg `m^2`. The system moves with a linear velocity of 2 m/s on a frictionless horizontal surface ?

Text Solution

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`L = m_(1)vr + m_(2)vr + lv//r = (3+1) xx 2 xx 0.3 + 0.14 xx (2//0.3) = 3.33 Js`, (r-radius of pulley)
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