An oxygen molecule has a mass of `5.3 xx 10^(-26)` kg anda moment of inertia of `1.94 xx 10^(-46) kg m^2` about an axis passing through the centre and perpendicular to the line joining the two oxygen atoms. The molecule is moving at a speed of 500 m/s and its rotational kinetic energy is two-thirds its translational K.E. Calculate its angular velocity.

Explanation

To solve the problem step by step, we will follow the given information and apply the relevant formulas.

### Step 1: Calculate the Translational Kinetic Energy (TKE)
The formula for translational kinetic energy is given by:

\[ TKE = \frac{1}{2} m v^2 \]
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