A metre scale of mass 100 gm is suspended freely at its end. It is pulled aside and swung about a horizontal axis with an angular velocity 5 rad/s. Calculate the height to which the centre of mass of the scale rises above its lowest position, assuming that there is no friction and air resistance. (given : length of meter scale used = 1m )

Explanation

To solve the problem, we will use the principle of conservation of energy. The initial energy of the system when the scale is swung will be converted into potential energy when the center of mass rises to a height \( h \).

### Step-by-Step Solution:

1. **Identify the Mass and Length of the Scale:**
- Mass of the scale, \( m = 100 \, \text{g} = 0.1 \, \text{kg} \)
- Length of the scale, \( L = 1 \, \text{m} \)

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