A solid body weighs 2.10 N in air. Its relative density is 8.4. How much will the body weigh if placed
(i) in water
(ii) in a liquid of relative density `1.2`?

Explanation

To solve the problem step by step, we will use the concepts of buoyancy and relative density.

### Given:
- Weight of the solid body in air (W) = 2.10 N
- Relative density of the solid (RD_solid) = 8.4
- Relative density of water (RD_water) = 1 (since relative density is compared to water)
- Relative density of the liquid (RD_liquid) = 1.2

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