The moment of a force of 5N about a point P is 2 Nm. Calculate the distance of point of application of the force from the point P.
Text Solution
AI Generated Solution
To solve the problem, we need to calculate the distance of the point of application of the force from point P using the relationship between moment (torque), force, and distance.
### Step-by-Step Solution:
1. **Understand the Formula for Moment of a Force**:
The moment (torque) \( M \) about a point is given by the formula:
\[
M = F \times d
...
The moment of a force of 10N about a fixed point O is 5 Nm. Calculate the distance of the point O from the line of action of the force.
The moment of a force of 50 N about a point is 5 Nm. Find the perpendicular distance of force from that point.
The moment of the force F acting at a point P, about the point C is
Find the torque of a force F=a(hati+2hatj+3hatk) N about a point O. The position vector of point of application of force about O is r=(2hati+3hatj-hatk) m .
Find the torque of a force F=(2hat(i) +hat(j)-3hat(k))N about a point O. The position vector of point of application of force about O is r = (2 hat(i) + 3 hat(j) - hat(k))m .
The distance of point p(3,4,5) from the YZ- plane is
The distance of the point P(3, -4) from the origin is
The distance of the point P(-6,8) from the origin is
Find the distances of the point P(2, 3, 2) from the coordinate planes.
ICSE-FORCE -EXERCISE 1( C) Multiple Choice questions