In Fig. 1.17 a roller of diameter 0.4m is raised on the pavement XY by forces `F_1 and F_2` each of magnitude 10N. Compare the torques produced by the two forces.
Text Solution
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Given `F_1=F_2=10N` Perpendicular distance of point of rotation X from the force `F_1` is `d_1=0.4 m` while that of force `F_2` is `d_2=1/2 times 0.4m=0.2m` `("Torque pr oduced by force" F_1)/ ("Torque pr oduced by force" F_2)= (F_1 times d_1)/(F_2 times d_2)` `=(10 N times 0.4 m)/ (10 N times 0.2m )=2/1`
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ICSE-FORCE -EXERCISE 1( C) Multiple Choice questions
