Calculate the power of an engine required to lift `10^(5)Kg` of coal per hour from a mone 360 m deep (Take g=10 m `s^(-2)`)

Explanation

To solve the problem of calculating the power of an engine required to lift \(10^5 \, \text{kg}\) of coal from a mine that is 360 m deep, we can follow these steps:

### Step 1: Identify the given data
- Mass of coal, \( m = 10^5 \, \text{kg} \)
- Acceleration due to gravity, \( g = 10 \, \text{m/s}^2 \)
- Height (depth), \( h = 360 \, \text{m} \)

### Step 2: Calculate the work done (W)
...