A pump is used to lift 500 kg of water from a depth of 80 m in 10 s .Calculate :
(a)the work done by the pump .
(b)the power at which the pump works,and
(c )the power rating of the pump if its efficiency is 40% (Take g =10 m `s^(-2)`) [Hint :Efficiency=`("use power")/("power input")]`

Explanation

To solve the problem step by step, we will calculate the work done by the pump, the power at which the pump works, and the power rating of the pump given its efficiency.

### Step 1: Calculate the Work Done by the Pump
The work done (W) by the pump can be calculated using the formula:
\[ W = mgh \]
where:
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