A truck eighine 1000 kg changes its speed from 36 km `h^(-1)` to 72 km `h^(-1)` in 2 minutes. Calculate (i) the work done by the engine, and in its power (g 10 m `s^(-2))`

Explanation

To solve the problem step by step, we will follow these steps:

### Step 1: Convert the initial and final speeds from km/h to m/s
The initial speed \( U_1 \) is given as 36 km/h. To convert this to m/s, we use the conversion factor \( \frac{5}{18} \).

\[ U_1 = 36 \, \text{km/h} \times \frac{5}{18} = 10 \, \text{m/s} \]
...