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A nut which can be broken by applying a ...

A nut which can be broken by applying a force of 40 kgf, is broken by using a nut cracker having its handle 20 cm long, by placing it at a distance 2 cm from the hinge. Calculate the minimum force needed to break the nut.

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To solve the problem, we will use the principle of moments, which states that the moment (or torque) about a pivot point (hinge) is equal for both the load and the effort applied. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Force required to break the nut (Load, \( F_L \)) = 40 kgf - Length of the nutcracker handle (Total length, \( L \)) = 20 cm - Distance from hinge to the load (Load arm, \( d_L \)) = 2 cm ...
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