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The critical angle for material of which...

The critical angle for material of which the equiangular prism ABC shown in figure is made, is `60^(@)`. A ray of light incident on the side AB of the prism is refracted along DE such that the angle it makes with the side AC is `150^(@)` and `angleEDB=90^(@)`. draw the path of the incident ray on the side AB (which travels along DE) and also the path along which the ray DE travels from the point E onwards.

Text Solution

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The completed diagram is shown in figure. Since the refracted ray DE is normal to the surface AB of the prism (i.e., `angler=0^(@)`), so the incident ray at the point D should also be normal to the surface AB so that `anglei=0^(@)`. at the point E, the angle of incidence for the ray DE is `150^(@)-90^(@)=60^(@)` which is equal to the critical angle, so the ray DE is refracted at `90^(@)`, i.e., it is refracted along EC.
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