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A postage stamp kept below arectangular...

A postage stamp kept below arectangular glass slab of refractive index `1*5` when viewed from vertically above it, appears to be raised by `7*0mm`. Calculate the thickness of the glass slab.

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To solve the problem of finding the thickness of the glass slab, we can follow these steps: ### Step 1: Understand the Problem We know that a postage stamp appears to be raised by 7 mm when viewed through a glass slab with a refractive index of 1.5. This apparent raise is due to the refraction of light as it passes through the slab. ### Step 2: Identify the Formula The normal shift (apparent raise) can be calculated using the formula: \[ \text{Normal Shift} = t \left(1 - \frac{1}{\mu}\right) \] where: - \( t \) is the thickness of the slab, - \( \mu \) is the refractive index of the slab. ### Step 3: Substitute Known Values Given: - Normal Shift = 7 mm, - Refractive Index \( \mu = 1.5 \). Substituting these values into the formula: \[ 7 = t \left(1 - \frac{1}{1.5}\right) \] ### Step 4: Simplify the Equation Calculate \( 1 - \frac{1}{1.5} \): \[ 1 - \frac{1}{1.5} = 1 - \frac{2}{3} = \frac{1}{3} \] Now, substitute this back into the equation: \[ 7 = t \left(\frac{1}{3}\right) \] ### Step 5: Solve for Thickness \( t \) To find \( t \), rearrange the equation: \[ t = 7 \times 3 \] \[ t = 21 \text{ mm} \] ### Step 6: Convert to Centimeters (if needed) Since 21 mm can also be expressed in centimeters: \[ t = 2.1 \text{ cm} \] ### Final Answer The thickness of the glass slab is: \[ \text{Thickness} = 21 \text{ mm} \text{ or } 2.1 \text{ cm} \] ---
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