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Without using tables, give the value of...

Without using tables, give the value of the following :
`"sec"(15pi)/(4)`

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To find the value of \( \sec\left(\frac{15\pi}{4}\right) \) without using tables, we can follow these steps: ### Step 1: Simplify the angle We start by simplifying the angle \( \frac{15\pi}{4} \). We can express it in terms of a more manageable angle by subtracting multiples of \( 2\pi \) (which is \( \frac{8\pi}{4} \)): \[ \frac{15\pi}{4} = \frac{16\pi}{4} - \frac{\pi}{4} = 4\pi - \frac{\pi}{4} \] ### Step 2: Determine the equivalent angle in standard position The angle \( 4\pi - \frac{\pi}{4} \) is equivalent to \( -\frac{\pi}{4} \) when considering the periodicity of the trigonometric functions. Since \( \sec(x) \) has a period of \( 2\pi \), we can also represent this as: \[ \sec\left(4\pi - \frac{\pi}{4}\right) = \sec\left(-\frac{\pi}{4}\right) \] ### Step 3: Identify the quadrant The angle \( -\frac{\pi}{4} \) lies in the fourth quadrant. In the fourth quadrant, the cosine function (and therefore secant) is positive. ### Step 4: Use the reference angle The reference angle for \( -\frac{\pi}{4} \) is \( \frac{\pi}{4} \). Thus, we can write: \[ \sec\left(-\frac{\pi}{4}\right) = \sec\left(\frac{\pi}{4}\right) \] ### Step 5: Calculate the secant Now, we need to find \( \sec\left(\frac{\pi}{4}\right) \). We know that: \[ \sec(x) = \frac{1}{\cos(x)} \] For \( x = \frac{\pi}{4} \): \[ \cos\left(\frac{\pi}{4}\right) = \frac{1}{\sqrt{2}} \] Thus, \[ \sec\left(\frac{\pi}{4}\right) = \frac{1}{\cos\left(\frac{\pi}{4}\right)} = \frac{1}{\frac{1}{\sqrt{2}}} = \sqrt{2} \] ### Final Result Therefore, the value of \( \sec\left(\frac{15\pi}{4}\right) \) is: \[ \sec\left(\frac{15\pi}{4}\right) = \sqrt{2} \]
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ICSE-TRIGONOMETRICAL FUNCTIONS -Exercise 4(d)
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