Suppose the six digit 1,2,4,5,6,7 are given to us and we have to find the total number of ways with no repetitions of digits which can be formed under different conditions.

Find the sum of all four digit numbers (without repetition of digits) formed using the digits 1,2, 3, 4, 5.

From the digits 1,2,3,4,5,6 how many three - digit odd numbers can be formed when the repetition of the digits is not allowed?

How many even numbers of 5 digits without repetition can be formed with the digits 1,2,3,4 and 5.

No. of even 6 digits numbers, without repetition of digits, using digits 1,2,3,4,5,6,7 are:

How many 4-digit numbers can be formed by using the digits 1 to 9 if repetition of digits is not allowed?

The sum of all five digit numbers formed with the digits 1,2,3,4,5 without repetition of digits are

How many three digit can be formed using the digits 1, 2, 3, 4, 5, without repetition of digits? How many of these are even?

How many 2- digits numbers can be formed from the digits 8,1,3,5 and 4 assuming repetition of digits is allowed?

How many three digit numbers can be formed by using the digits, 0,1,2,3 (repetition of digits is allowed)

Statement-1: A 5-digit number divisible by 3 is to be formed using the digits 0,1,2,3,4,5 without repetition, then the total number of ways this can be done is 216. Statement-2: A number is divisible by 3, if sum of its digits is divisible by 3.